Ask question

Ask question

All categories

3 years ago

13

Wich ratio is equivalent to 4:10

1 answer:

Kisachek [45]3 years ago

6 0

The next one would be 8:20 or 2:5 and many others, these are just a few

You might be interested in

Ray’s weight increased by 11% in the last two years. If he gained 16.5 pounds, what was his weight two years ago?

kap26 [50]

2 years ago he weighed 119.5 pounds

4 0

3 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$

So the ratio of the area of the circle to the original square is:

$\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}$

Given:

side length (s) = 6 in
radius (r) = 6 ÷ 2 = 3 in

$\implies \sf \textsf{Area of square}=6^2=36\:in^2$

$\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)$

Ratio of circle to square:

$\implies \dfrac{28}{36}=\dfrac{7}{9}$

5 0

2 years ago

Xavier rides his bike 5 1/4 miles or 82% of his goal for the day. What is his goal for the day?

Leno4ka [110]

Use ratio and proportion

5.25/x= 82/100
cross multiply
82 x= 525
x= 6.4 miles

Hope this helps

8 0

3 years ago

Taisha uses the elliptical cross- trainer at the gym. Her general goal is to burn 280 calories per workout, but she varies by as

Fed [463]

Given - Taisha has a general goal is to burn the 280 calories.

she is varies by the 25 calories.

Find out the maximum and minimum of calories burn by the taisha.

To proof -

let us assume that the calories burn by the taisha be x.

as given the calories are varies by the 25 calories.

then the maximum calories equation becomes

x-25 = 280

x = 280 + 25

x = 305

the maximum calories burn by the taisha is 305 calories.

minimum calories equationbecomes

x + 25 = 280

x = 255

The minmum calories burn by the taisha is 255 calories.

Hence proved

8 0

3 years ago

Read 2 more answers

Consider rolling two fair dice and observing the number of spots on the resulting upward face of each one. Letting A be the even

Allushta [10]

Answer:

$P(E|A)= \frac{10}{11}$

Step-by-step explanation:

Given

Two rolls of die

$E \to$ one of the outcomes is 6

$A \to$ atleast one is 6

Required

P(E|A)

First, list out the outcome of each

$E = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

So:

$P(E|A)= \frac{n(E\ n\ A)}{n(A)}$

Where:

$E\ n\ A = \{(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)\}$

$n(E\ n\ A) = 10$

$n(A) = 11$

So:

$P(E|A)= \frac{10}{11}$

7 0

2 years ago