Anybody know the answer to this?
2 answers:
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Answer:
The critical value for a 98% CI is z=2.33.
The 98% confidence interval for the mean is (187.76, 194.84).
Step-by-step explanation:
We have to develop a 98% confidence interval for the mean number of minutes per day that children between the age of 6 and 18 spend watching television per day.
We know the standard deveiation of the population (σ=21.5 min.).
The sample mean is 191.3 minutes, with a sample size n=200.
The z-value for a 98% CI is z=2.33, from the table of the standard normal distribution.
The margin of error is:
With this margin of error, we can calculate the lower and upper bounds of the CI:
The 98% confidence interval for the mean is (187.76, 194.84).
Answer:
Mean
Step-by-step explanation:
The most common measures of central tendency are mode, median and mean.
The mode of the data set is the value that is repeated the most. In this case, the mode is $6 (appears twice), which does not support the raise claim of the employee.
The median is the central value of the data set. In this case, the median is also $6 (third highest value), which does not support the raise claim of the employee.
The mean of the salaries is:
Since the mean is greater than the employee's current wage, it would best support his request to be paid more.