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yanalaym [24]
2 years ago
9

Question is in the image

Mathematics
2 answers:
12345 [234]2 years ago
7 0

Answer:

Step-by-step explanation:

A, or 3

Luba_88 [7]2 years ago
3 0

Answer:

A: 3 hours.

Step-by-step explanation:

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A student would write an equation such as 2x + 38 = 180 for which set of angles?
Rzqust [24]

Answer:

x=71

Step-by-step explanation:

3 0
2 years ago
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Pls help!!!<br><br> Question in the picture
Wewaii [24]

Answer:

-7, -\pi -\sqrt{3} , 9

Step-by-step explanation:

6 0
2 years ago
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Center: (-2,5), radius:7
Firlakuza [10]

Answer:

(x + 2)² + (y - 5)² = 7²

Step-by-step explanation:

Incomplete question.  I believe you meant, "write the equation of the circle with center at (-2, 5) and radius 7.

That would be:

(x + 2)² + (y - 5)² = 7²

5 0
3 years ago
What are equivalent expression for 6x+1-(3x-1)
beks73 [17]

Answer:

3x + 2

Step-by-step explanation:

6x + 1 - (3x-1) < distribute the negative sign into the expression

6x + 1 -3x + 1 < combine like terms

6x - 3x = 3x

1 + 1 = 2

our simplified expression is:

3x + 2

8 0
3 years ago
How do you evaluate sin(13π/12)?
Alekssandra [29.7K]

13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0

Recall the double angle identity,

sin^2(x) = (1 - cos(2x))/2

If we let x = 13pi/12, then

sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]

where we took the negative square root because we expect a negative value.

Now, because cosine has a period of 2pi, we have

cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2

Then

sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]

sin(13pi/12) = - sqrt[2 - sqrt[3]]/2

7 0
2 years ago
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