All categories

3 years ago

Help me with this please!!!!!!!!!

Mathematics

2 answers:

IrinaVladis [17]3 years ago

8 0

Answer:

d = 17.58

Step-by-step explanation:

d = √(x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2

P1(0, 0, 0) P2(8, 7, 14)

Substitute the values in the above equation and you will get

d = √(8 - 0)^2 + (7 - 0)^2 + (14 - 0)^2

= √(64 + 49 + 196)

= √309

= 17.58

Anastasy [175]3 years ago

3 0

Answer:

The answer is 17.58

You might be interested in

Susan enlarged to scale a rectangle with a height of 4 cm and length of 11 cm on her computer. The length of the new rectangle i

Anvisha [2.4K]

The height is going to be 9.5

6 0

3 years ago

8x^3y^4-22x^5y^6 gcf

schepotkina [342]

Don't trust those link my cuz

5 0

3 years ago

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

6 0

3 years ago

Help me please! which one is correct?

Flauer [41]

Answer:

yes you are correct your very smart

Step-by-step explanation:

6 0

3 years ago

A function f is defined by f(x) = 2x - 3. By writing the full working, write the values of (a) f(0) (b) f(-2) (c) f(3) (d) f(-1)

AlladinOne [14]

A) f(x) = 2x - 3
f(0) = 2(0) - 3
f(0) = 0 - 3
f(0) = -3

b) f(x) = 2x - 3
f(-2) = 2(-2) - 3
f(-2) = -4 - 3
f(-2) = -7

c) f(x) = 2x - 3
f(3) = 2(3) - 3
f(3) = 6 - 3
f(3) = 3

d) f(x) = 2x - 3
f(-1) = 2(-1) - 3
f(-1) = -2 - 3
f(-1) = -5

6 0

3 years ago