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maw [93]
3 years ago
12

Which graph represents the function below?

Mathematics
2 answers:
krok68 [10]3 years ago
4 0

Answer:

It is A.

Step-by-step explanation:

Hope this helped have an amazing day!

KATRIN_1 [288]3 years ago
3 0
The answer to this problem is A
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Please help with this 2+4(5-8). step by step
igor_vitrenko [27]
NAMASTE

HERE IS YOUR ANSWER:

2+4(5-8)
We know, the BODMAS (bar, order, multiply, add, subtract) rule. so we will solve it as follows:


➡2+4(-3) (✔ 5-8= -3)

➡2+(-12) (✔ 4(-3)= -12)

➡2-12 (✔ +(-12) = -12)

➡ \boxed{-10}
8 0
3 years ago
Read 2 more answers
Cual es el valor de la operación ((f(g)(2)​
lana [24]

Answer:

2fg

Step-by-step explanation:

5 0
2 years ago
Which of the following is NOT true about complementary angles? (A) Both angles are acute. (B) Neither angle can be a right angle
tester [92]

Answer:

(D) Their angle measures cannot be equal.

Step-by-step explanation:

(A) It's fine if both angles are acute.

(B) None of the angles can be a right angle.

(C) Their sum has to be 90°.

(D) Their angle measures can be equal.

3 0
3 years ago
Read 2 more answers
What is the square root of -2i?
Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of z=0-2i. First, convert from Cartesian to polar form:

r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2

\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}

z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})

Next, use the formula \displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr] where \displaystyle k=0,1,2,...\:,n-1 to find the square roots:

<u>When k=1</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]

\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)

\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i

<u>When k=0</u>

<u />\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]

\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)

\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i

Thus, the square roots of -2i are 1-i and -1+i

4 0
2 years ago
To find the y intercept of the graph of a linear equation we.
Lelechka [254]

Answer:

B

Step-by-step explanation:

A y-intercept's x will always be zero, there is no movement along the horizontal axis. Since you are looking for a y-intercept, you will solve for y.

3 0
3 years ago
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