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natulia [17]
3 years ago
12

Find the area of the shaded region in terms of x.

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

35x^2 - 71x + 15

Step-by-step explanation:

look at the photo

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How do I solve this problem? It’s been awhile since I’ve done math
Helga [31]

Answer:

y = C/h - 2

Step-by-step explanation:

Equation

C = (2 + y)*h

Solution

C = (2 + y)*h                          Divide by h

C/h = (2 + y)*h/h

C/h = 2 + y                            Subtract 2 from both sides

C/h-2 = 2-2+ y                      Combine

C/h - 2 = y

3 0
1 year ago
{A number line from negative 10 to 10 with tick marks every 1 unit. A closed dot is at negative 3 with a ray pointing left from
maks197457 [2]
Draw a number line from -10 to +10 with tick marks (division lines) every 1 unit.  Now find the origin (in the middle of the line you have just drawn).  Now move your pencil point 3 units to the left and plot a dark (closed) dot there.  Then draw a ray from that closed dot to the left.  Apparently we cannot extend that ray beyond -10.

(-10,-3] would be my representation of this situation.

6 0
3 years ago
Help please I need to find the area I don’t know how thanks
otez555 [7]

Answer:

49.62

Step-by-step explanation:

You can start by dividing the shape into 2 separate rectangles to make calculating the area easier.

9.3 x 2.4 = 22.32

10.5 x 2.6 = 27.3

Then, add the areas of the two separate rectangles to find the total area of the shape.

22.32 + 27.3 = 49.62. Hope that helped

4 0
3 years ago
True or false? A convex shape curves outwards.
Margaret [11]
The answer is true. Hope this helps. Mark brainest

6 0
3 years ago
Read 2 more answers
What’s the equation for the order pairs (1,-5) and (-2,5)
liq [111]

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})\qquad
(\stackrel{x_2}{-2}~,~\stackrel{y_2}{5})
\\\\\\
slope = m\implies
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-(-5)}{-2-1}\implies \cfrac{5+5}{-2-1}\implies \cfrac{10}{-3}


\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-(-5)=-\cfrac{10}{3}(x-1)\implies y+5=-\cfrac{10}{3}x+\cfrac{10}{3}
\\\\\\
y=-\cfrac{10}{3}x+\cfrac{10}{3}-5\implies y=-\cfrac{10}{3}x-\cfrac{5}{3}

6 0
3 years ago
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