Answer:
D is the answer
Step-by-step explanation:
For a: g(x) = 1 when x = 1, for f(x) 1^2 - 2(1) + 2 = 1, a is true.
For b: Both functions do have all real numbers for their domain, b is true
For c: the y-intercept of g(x) is x = 0, for f(x), it is 0^2 - 2(0) + 2 = 2, c is true
For d: g(3) = 7, f(3) = 3^2 - 2(3) + 2 = 5, d is false.
Answer:
your answer is y = 8/3
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
<h3>How to determine the zeros of the function?</h3>
The function is given as:
f(x) = x^3 + 3x^2 + 2x
Factor out x in the above function
f(x) = x(x^2 + 3x + 2)
Set the function to 0
x(x^2 + 3x + 2) = 0
Factorize the expression in the bracket
x(x + 1)(x + 2) = 0
Split the expression
x = 0, x + 1 = 0 and x + 2 = 0
Solve for x
x = 0, x = -1 and x = -2
Hence, the zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2
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Answer:
(1,4)
Step-by-step explanation:
The two lines intersect at 1,4 when you graph them
The first equation is already in slope intercept from, so you know the y-int. is 7 and the slope is 3. However, the second equation must be put in slope int. form.
5x+2y=3
move the y to the other side
5x=3-2y
move the 3 to the other side, so the y variable is by itself
5x-3=-2y
divide by -2 to the equation is equal to y
(-5x/2)+(3/2)=y
you now know the y int. of the second equation is 3/2 and the slope is -5/2
know that you know the slop int. formulas for both equations you can graph them
