Dt = 2(0.8)t = 1.6t = 1.6(10) - 1.6(5) = <span>8 m/s</span>
The answer is 93
If we sorted out the number of each hours, the sequence will look like this
57 _ 69 _ 81 _ x _ 105
(in which x is the fourth hour of work)
We can see from the sequence that each hours, the mailman add additional 12 letters.
(69 - 57 = 12)
(81 - 69 = 12) . . . . proof
So, the amount of letters on the fourth hour would be:
81 letters + 12 letters = 93 Letters
Answer:
k = -3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
-9 = k - 6
<u>Step 2: Solve for </u><em><u>k</u></em>
- Add 6 to both sides: -3 = k
- Rewrite: k = -3
y=19x+9 would be the rule
