All categories

3 years ago

3 (bx - 2ab) = b (x - 7a) + 3ab solve for x

2 answers:

4 0

3(bx - 2ab) = b(x - 7a) + 3ab
<=> 3bx - 6ab = bx - 7ab + 3ab
<=> 3bx - bx = 6ab - 7ab + 3ab
<=> 2bx = 2ab
<=> x = a

chubhunter [2.5K]3 years ago

3 0

Answer:

The value of x = a.

Step-by-step explanation:

Consider the provided equation.

3 (bx - 2ab) = b (x - 7a) + 3ab

Use the distributive property: a(b+c)=ab+ac

3bx - 6ab = bx - 7ab + 3ab

Now add the like variable.

3bx - 6ab = bx - 4ab

Subtract bx and add 6ab on both sides.

3bx - 6ab - bx + 6ab = bx - bx - 4ab + 6ab

2bx = 2ab

Divide both the side by 2b.

x = a

Hence, the value of x = a.

You might be interested in

For the first 30 km, the bicyclist rode with a speed of v km/hour. For the remaining 17 km he rode with a speed which was 2 km/h

damaskus [11]

Answer:

t= 2.52 hours

Step-by-step explanation:

It is given that for first 30 km, the speed of bicyclist is v km/hour

time taken to cover first 30 km is given by

$t_{1} =\frac{30}{v}$ ( $time=\frac{distance}{speed}$ )

for next 17 km the speed of bicyclist is 2 km/hour greater than his original speed

so the speed to cover next 17 km = v+2

time taken to cover next 17 km is given by

$t_{2} =\frac{17}{v+2}$

now total time t spent by the bicyclist to cover entire trip is given by

$t=t_{1} +t_{2}$

$t=\frac{30}{v} +\frac{17}{v+2}$

now if v=18 , we have

$t=\frac{30}{18} +\frac{17}{20}$

now to add fractions we make the denominator same

Hence we will find the LCM of 18 and 20

LCM of 18 and 20 = 180

now we need to make both the denominator equal to 180

$t=\frac{30(10)}{18(10)} +\frac{17(9)}{20(9)}$ $t=\frac{300}{180} +\frac{153}{180} =\frac{300+153}{180}$

$t=\frac{453}{180} =2.52$ hours (approx)

7 0

3 years ago

14. What point is in the first quadrant? a. (1,-2) b. (-2.1) C (1,2) d. (-2,-1)

Viefleur [7K]

Mf- we need a picture

4 0

2 years ago

Convert 8.1616 to a fraction

loris [4]

The answer is 808/99

7 0

3 years ago

Read 2 more answers

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot

MaRussiya [10]

I found the corresponding image. Pls. see attachment.

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D

8 0

3 years ago

which graph could represent y, the amount owed on a car loan, as regular payments are made each month, x?

lianna [129]

Answer is the second graph

The more payments you pay, the less money you owe.

4 0

3 years ago

Read 2 more answers