The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
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Plug in 2 for t.
=> -16*(2^2) +80*2 +3
=> -16*4 +160 +3
=> -64+163
=> 99
Answer:
AC = 10
Step-by-step explanation:
Do you really need the explanation it seems like you are taking a test. I answered one of your questions a few seconds ago.
a^2+b^2=c^2.
8^2 + 6^2 = c^2
64 + 36 = c^2.
100 = c^2.
Square root of it all equals to
c = 10.
Answer:
a). 8(x + a)
b). 8(h + 2x)
Step-by-step explanation:
a). Given function is, f(x) = 8x²
For x = a,
f(a) = 8a²
Now substitute these values in the expression,
= 
= 
= 
= 8(x + a)
b). 
= 
= 
= 
= (8h + 16x)
= 8(h + 2x)
Answer:
<h3>The answer is 17.80 units</h3>
Step-by-step explanation:
The distance between two points can be found by using the formula
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
(-8,19) and (3,5)
The distance between them is
We have the final answer as
<h3>17.80 units to the nearest hundredth</h3>
Hope this helps you
