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4 years ago

I need someone to help me with this really quick!

Mathematics

2 answers:

vodomira [7]4 years ago

6 0

Answer:

jajajajajajajajajajajqjajajqjajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajajaja

Lunna [17]4 years ago

5 0

The expensive one is the turkey

the least expensive one is the roast beef

I do know when I hange the mixed fraction to a whole number or proper fraction

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Examine the two similar triangles below solve for y need by 11:59 for final exam

Sloan [31]

Answer:

Step-by-step explanation:

dont listen to me this is a wrong answer

8 0

3 years ago

Tell whether x and y show direct variation y=x+1

konstantin123 [22]

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Answer:

variation is NOT direct

Step-by-step explanation:

The +1 tells you the variation is not direct. The equation of direct variation is of the form ...

y = kx

with nothing added.

7 0

3 years ago

Obtain the general solution of y ln x ln y dx + dy = 0

oksano4ka [1.4K]

Dy/dx = -y inx iny

(y in x in y) dx + dy = 0

(y in x in y ) dx = - dy

(in x )dx = - (1/ y in y) dy

you just need to integrate both sides

Hope this helps

4 0

4 years ago

The sum of the ages of the father and his son is 42 years. The product of their ages is 185. Find the age of the father and the

Iteru [2.4K]

Let f and s be the ages of the father and the son. We have

$\begin{cases}f+s=42\\fs=185\end{cases}$

From the first equation we derive

$f=42-s$

Substitute this expression for f in the second equation and we have

$(42-s)s=185 \iff -s^2+42s-185=0 \iff s^2-42s+185=0$

The solutions to this equation are s=5 or s=37

Since the sum of the ages must be 42, the solutions would imply

$s=5 \implies f=37,\quad s=37\implies f=5$

We can only accept the first solution, since the second would imply a son older than his father!

4 0

3 years ago

Theoretically, if a month is chosen 300 times,

horsena [70]

Answer:

75 times.

Step-by-step explanation:

Well there are 12 months and 3 of them start with the letter J, so theoretically, 25% of the months chosen will start with the letter J because $\frac{3}{12}=\frac{1}{4}$ , which is 25%. 25% of 300 (or $\frac{300}{4}$ , for those who like fractions) is 75, so theoretically, we can expect a month that starts with the letter J 75 times.

Hope this helps!

P.S: Please mark me as brainliest!

6 0

3 years ago