For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
To find perimeter you add up all the sides so 5cm+6cm+17cm+8cm. This will get you 36cm.
29 is the answer. 32 can be divided by , 42 can also, and 15 can be divided by 5.
Answer:
Step-by-step explanation:
First we know triangle WXY is an equilateral which means all its angles are 60 degrees.
Next we know triangle WZY is an isosceles so it has 2 angles that are equal to each other.
Since angle Z is an obtuse angle. We can calculate the other angles which we will assume are equal because 138+138 is greater than 180 degrees.
180-138 = 42
42/2 = 21 <-- divide by 2 because we know we're looking for 2 angles
For the angles of WXY.
60-21 = 39
Therefore
Angle I = 60
Angle 2 = 39
Angle 3 = 21
Angle 4 = 39
Angle 5 = 21
