Answers:
- Exponential and increasing
- Exponential and decreasing
- Linear and decreasing
- Linear and increasing
- Exponential and increasing
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Explanation:
Problems 1, 2, and 5 are exponential functions of the form
where b is the base of the exponent and 'a' is the starting term (when x=0).
If 0 < b < 1, then the exponential function decreases or decays. Perhaps a classic example would be to study how a certain element decays into something else. The exponential curve goes downhill when moving to the right.
If b > 1, then we have exponential growth or increase. Population models could be one example; though keep in mind that there is a carrying capacity at some point. The exponential curve goes uphill when moving to the right.
In problems 1 and 5, we have b = 2 and b = 1.1 respectively. We can see b > 1 leads to exponential growth. I recommend making either a graph or table of values to see what's going on.
Meanwhile, problem 2 has b = 0.8 to represent exponential decay of 20%. It loses 20% of its value each time x increases by 1.
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Problems 3 and 4 are linear functions of the form y = mx+b
m = slope
b = y intercept
This b value is not to be confused with the previously mentioned b value used with exponential functions. They're two different things. Unfortunately letters tend to get reused.
If m is positive, then the linear function is said to be increasing. The line goes uphill when moving to the right.
On the other hand if m is negative, then we go downhill while moving to the right. This line is decreasing.
Problem 3 has a negative slope, so it is decreasing. Problem 4 has a positive slope which is increasing.
Answer:
the approximate probability that the insurance company will have claims exceeding the premiums collected is 
Step-by-step explanation:
The probability of the density function of the total claim amount for the health insurance policy is given as :

Thus, the expected total claim amount
= 1000
The variance of the total claim amount 
However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100
To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :
P(X > 1100 n )
where n = numbers of premium sold





Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is 
Answer
Simplifying
9x + -7i = 3(3x + -7u)
Reorder the terms:
-7i + 9x = 3(3x + -7u)
Reorder the terms:
-7i + 9x = 3(-7u + 3x)
-7i + 9x = (-7u * 3 + 3x * 3)
-7i + 9x = (-21u + 9x)
Add '-9x' to each side of the equation.
-7i + 9x + -9x = -21u + 9x + -9x
Combine like terms: 9x + -9x = 0
-7i + 0 = -21u + 9x + -9x
-7i = -21u + 9x + -9x
Combine like terms: 9x + -9x = 0
-7i = -21u + 0
-7i = -21u
Solving
-7i = -21u
Solving for variable 'i'.
Move all terms containing i to the left, all other terms to the right.
Divide each side by '-7'.
i = 3u
Simplifying
i = 3u