Pretty sure the distance is 8 units
Answer:
Step-by-step explanation:
let score in fourth test=x
88+98+79+x=80×4
265+x=320
x=320-265=55
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Answer:
To find volume of a tent this would be your formula:
start by taking the base of the triangle on your tent typically located in the front
1/2 (height) (width) to get your area (DONT SKIP THIS STEP)
Then take your area you just calculated and do
(area) (length)
Let me give you an example:
in the picture below
height: 3 cm
length: 8 cm
Width: 12 cm
Next do your first formula:
1/2 (3)(12)= 18 cm
(Calculation of one face)
then your second:
(18)(8)= 144 
Hopefully this guide helped you sorry i couldn't answer your question without a picture!
