1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GalinKa [24]
3 years ago
8

kim owes $870.00 on her mastercard account. She returns two items costing $35.90 and $150.00 and receive credits for these on th

e account. Next, she makes a purchase of $82.50, and then two more purchases of $10.00 each. She makes a payment of $500.00. She then incurs a finance charge of $37.23. How much does she still owe?
Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

She has 499.3$

Step-by-step explanation:

870+35.90+35.90+150-82.50-10-500

You might be interested in
Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]
Anit [1.1K]

Answer:

The answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

Step-by-step explanation:

\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}

Solve the L.H.S part:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]

After calculating the L.H.S part compare the value with R.H.S:

\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\

\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\

In equation (i) multiply by 3 and subtract by equation (iii):

\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to  c= - \frac{1}{2}

put the value of c in equation (i):

\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\

In equation (ii) multiply by 3 then subtract by equation (iv):

\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\

put the value of d in equation (iv):

\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2

The final answer is "\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}".

4 0
3 years ago
If f(x)= 3x + 1 and f^(-1)= x-1/3, then the ordered pair of f^(-1)(10)=
iragen [17]

The answer is B

The correct inverse of 3x+1 is actually (1/3)x - 1/3

plug in 10 to the inverse

10/3 - 1/3 = 9/3 or 3

this gives you the point (10,3)

8 0
3 years ago
Someone help me answer this and show work please!
timurjin [86]

Answer:

Simple

Rise/Run

for one week they run 10 miles

2 weeks 20 miles

3 weeks 30 miles

4 weeks 40 miles

the rate of change would be 10/1 (Why? Because you rise +10 each time per week.)

divide that it would be 10 (:

gOoD lUCk

second answer copied me so.

7 0
3 years ago
Which option lists am expression that is not equivalent to 4^2/3
Vesnalui [34]

remember that

x^{\frac{a}{b}}=\sqrt[b]{x^a}

also x^{-a}=\frac{1}{x^a}

and (a^b)^c=a^{bc}


so

4^{\frac{2}{3}}


first one, that one is clearly not equal since 0.25≠4

2nd one, 0.25=1/4, so 0.25^{\frac{-2}{3}}=(\frac{1}{4})^{\frac{-2}{3}=  \frac{1}{(\frac{1}{4})^{\frac{2}{3}}}=4^{\frac{2}{3}}, which matches

3rd one, \sqrt[3]{16}=\sqrt[3]{4^2}=4^{\frac{3}{2}}, which matches

4th one (\sqrt[3]{4})^2=(4^{\frac{1}{3}})^2=4^{\frac{2}{3}} which matches


answer is 0.25^{\frac{2}{3}}

4 0
3 years ago
A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random
Alenkasestr [34]

Answer:

a. Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

b. t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

c. p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2>0

Our notation on this case :

n_1 =78 represent the sample size for group 1

n_2 =21 represent the sample size for group 2

\bar X_1 =92.88 represent the sample mean for the group 1

\bar X_2 =86.90 represent the sample mean for the group 2

s_1=15.34 represent the sample standard deviation for group 1

s_2=8.99 represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom. If we replace the values given we have:

t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

Now we can calculate the degrees of freedom given by:

df=78+21-2=97

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

6 0
3 years ago
Other questions:
  • 1. A factory worker in Cambodia makes 320,000 Cambodian Riels per month. If 1 U.S. dollar equals 4000 Cambodian Riels, how much
    7·1 answer
  • Which pair represents equivalent ratios? A Begin fraction . . . 2 over 3 . . . end fraction . . . and . . . begin fraction . . .
    12·2 answers
  • The sides of a cube are measured in whole centimeters. Which of the following could not be the cube's volume?
    8·2 answers
  • PLEASE PLEASE HELP ME WITH THIS QUESTION
    15·2 answers
  • I NEED ANSWER ASAP! I HAVE A LOT OF POINTS, I WILL GIVE 50 POINTS AND BRAINLIEST TO FIRST ANSWERRRRRR!
    14·2 answers
  • Determine an expression that would represent the area of the figure shown.
    6·1 answer
  • Find the coordinates for the midpoint of the segment with endpoints given (3,5)<br>(-2,0)​
    13·1 answer
  • Please help ! mathhhhh
    6·1 answer
  • The weight of a boy was 15kg last year. If his weight increases by 3kg this year, find the percentage increase in his weight.
    12·1 answer
  • Which of the following statements describe this sequence: 3, 6, 9, 12...?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!