All categories

2 years ago

Which expressions do you get when you eliminate the negative exponents of .........

Mathematics

1 answer:

kvasek [131]2 years ago

5 0

Answer:

D. 4(a^2)(a^3)/16(b)(b^2)

Step-by-step explanation:

You might be interested in

If xr-st=r, which expression represents x

Alexus [3.1K]

Answer:

To get an expression relating to x you need to have x alone on one side of your equation. ie x =

Try this:

rx - st = r

remove st from the rx side

rx = r + st

now divide by r

x = (r + st)/r

You now have your expression relating to x

7 0

2 years ago

Consider a Poisson distribution with μ = 6.

bearhunter [10]

Answer:

a) $P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b) f(2) = 0.04462

c) f(1) = 0.01487

d) $P(X \geq 2) = 0.93803$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 6$

a. Write the appropriate Poisson probability function.

Considering $\mu = 6$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b. Compute f (2).

This is P(X = 2). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

Then

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803$

$P(X \geq 2) = 0.93803$

5 0

2 years ago

The hydra was a one-headed monster but when iris cut off ,2 heads grow back in its place. If a hero tried to conquer it by cutti

Cerrena [4.2K]

Answer:

3 days: 8 heads.

10 days: 1024 heads.

Step-by-step explanation:

If each time the hero cuts off all the heads, then the amount doubles each time. This can also be represented using powers of 2, with 2^n, where n is the number of days.

2^1 = 2, so two heads the first time he cuts it.

2^2 = 4, so four heads the second time he cuts it.

With three, 2^3 is 8 so there are 8 heads.

With ten, 2^10 is 1024 so there are 1024 heads.

4 0

2 years ago

Please help me because I don't understand how to do it.:)

Fofino [41]

Answer:

V =84.78 inches ^2

Step-by-step explanation:

The volume of a cylinder is given by

V= pi *r^2 h

We know h= 12 inches

and r = 1.5 inches

V = pi * (1.5)^2 * 12

V = pi * 2.25*12

V = 27 pi

If we approximate by 3.14

V = 3.14 (27)

V =84.78 inches ^2

6 0

2 years ago

The sum go 4 consecutive numbers is 326

cestrela7 [59]

80,81,82,83 are consecutive numbers that add up to 326.

7 0

2 years ago