Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula

The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.

![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 

=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Answer:
y = (6/11)x + 13/11
Step-by-step explanation:
y = mx + c
m = (-1-5)/(-4-7) = -6/-11 = 6/11
y = (6/11)x + c
When x = 7, y = 5
5 = (6/11)(7) + c
5 = 42/11 + c
c = 5 - 42/11
c = 13/11
y = (6/11)x + 13/11
11y = 6x + 13
Answer:
18.5
Step-by-step explanation:
Since she was paid $111 for 6 hours, you divide 111/6 to get 18.5