Answer:
0.5934% probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Playing at an NCAA college.
Event B: Being drafted by the MLB.
6.9% will play in an NCAA college
This means that 
8.6% of the college players will go on to be drafted by the MLB.
This means that 
What is the probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB?



0.5934% probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB
Answer:
171
Step-by-step explanation:
calculator
LnA +LnB= LnA.B
so we get <span>Log3(X-5)+log3(x+3)=Ln3(x-5)(x+3)=2 implies
</span>(x-5)(x+3)=2^3=8, so we can solve easily the quadratic equation
x^2-2x-23=0, there are two solution x=1 -sqrt(24), and x=1+sqrt(24)
1 - 2 = 1 3 - 4 = 1 5 - 9 = 4 9 - 9 = 0 7 - 14 = 7 21 - 0 = 21 8 - 12 = 5 4 - 85 = 81 x is 8 and z is 5. x - z = 3 d is 2 and 8 is w and 17 is y. d - w - y = 7
Answer:
Probability is 0.3506
Step-by-step explanation:
We are given
mean is 8mm
so, 
standard deviation is 2.2 mm
so, 
x-varies from 7mm to 9mm
At x=7:
we can use formula

we can plug values


At x=9:
we can use formula

we can plug values


So, z is between -0.45455 and 0.45455

now, we can use normal distribution table
and we get
Probability is 0.3506