Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD =
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
=
=
= 0.6
Step-by-step explanation:
We are dealing with theoretical probability. This means that our probability of said outcome is
where x is the outcome we want, and y is the total number of outcomes possible.
28. There is 3 triangles out of 6 polygons so the probability is 1/2.
29.There is 1 Pentagon so the probability is 1/6.
30. This is a complement to question 28. A complement is the inverse of the problem. A complement and its original add to 1 so the probability of both getting a triangle is 1/2.
31. There is 4 non quadraletrial so the probability is 2/3.
32. There is 3 figures that has more sides than three so 1/2 is the probability.
33.There is only multi right angles figures so 1/2 is the probability.
34. There is 30 days in April so the probability it's the 29th is
35. There is 31 days in July and 15 days after the 16th. So the probability
is
Answer:
Step-by-step explanation:
The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.
There is no horizontal asymptote because the numerator is of higher degree than the denominator.
When you divide the numerator by the denominator, you get ...
y = (x +9) +60/(x -7)
Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.
