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DENIUS [597]
3 years ago
8

Lamar needs to find the sum of 3/6 and 2/3 could he multiple the denominator to find a common denominator explain the answer

Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0
Yes he could multiply he denominators 
1) Common Denominator= 6
2) at the numerators 
3) Answer= 5/6
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The value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

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The attachment represents the proper format of the question

The summation expression is given as:

\sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y

Expand the radicands

\sqrt{x^2y^2 * y} + 2\sqrt{x^2y^4* x} + xy\sqrt y

Evaluate the square roots

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Add the like terms

2xy\sqrt{y} + 2xy^2\sqrt{x}

Hence, the value of the expression \sqrt{x^2y^3} + 2\sqrt{x^3y^4} + xy\sqrt y is 2xy\sqrt{y} + 2xy^2\sqrt{x}

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