Rotate the point 603 degrees to within 10 degrees

Binomial theorem Expand (5 - y)3

Snowcat [4.5K]

Answer:

(5 - y) ^3 = 125 - 75y + 15y^2 - y^3

Step-by-step explanation:

Binomial expression

1

1. 1

1. 2. 1

1. 3. 3. 1 --------power of 3

( 5 - y) ^3

( 5 - y) (5 - y) (5 - y)

( a + b) ^3 = a^3 + 3a^2b + 3ab^2 + b^3

a = 5

b = -y

( 5 - y) ^2 = ( 5 - y) (5 - y)

= 5( 5 - y) - y(5 - y)

= 25 - 5y - 5y + y^2

=(25-10y+y^2)

( 25 - 10y + y^2)( 5 - y)

= 5(25 - 10y + y^2) - y( 25 - 10y + y^2)

= 125 - 50y + 5y^2 - 25y + 10y^2 - y^3

Collect the like terms

= 125 - 50y - 25y + 5y^2 + 10y^2 - y^3

= 125 - 75y + 15y^2 - y^3

7 0

3 years ago

Parker Middle School's chior needs to raise $480 for an upcoming trip they will take. At their first fundraising project, they r

harkovskaia [24]

The money does the choir still need to raise is $180.

Step-by-step explanation:

The money needed to be raised by the choir for an upcoming trip = $480.

It is given that, the money needed was raised in two fundraising projects.

During the first fundraising project :

The choir raised 25% of the money needed for the trip.

⇒ 25% of 480

⇒ (25/100) × 480

⇒ (1/4) × 480

⇒ 120

Therefore, the first fundraising project raised $120.

During the second fundraising project :

The choir raised 3/8 of the money needed for the trip.

⇒ 3/8 of 480

⇒ (3/8) × 480

⇒ 3 × 60

⇒ 180

Therefore, the second fundraising project raised $180.

To find the money does the choir still need to raise :

You need to find the remaining amount from the 480 after raising money from the two fund raising projects.

For that, find out how much you raised from those fund raising projects and subtract it from the 480.

Money needed = Total money required for the trip - Raised money

⇒ 480 - (120+180)

⇒ 480 - 300

⇒ 180 dollars.

The money does the choir still need to raise is $180.

6 0

3 years ago

There are about 10^24 stars in the universe. Each galaxy has approximately the same number of stars as the Milky Way Galaxy. Abo

maks197457 [2]

Answer:

$10^{13}$ galaxies.

Step-by-step explanation:

There are about $10^{24}$ stars in the universe.

The Milky Way galaxy $10 * 10^{10}$ stars.

All we need to do to find the number of galaxies is to divide the total number of stars in the universe by the number of stars in the Milky Way:

Number of galaxies = (Number of stars in the universe) / (Number of stars in the Milky Way)

Number of galaxies = $\frac{10^{24}}{10 * 10^{10}}$

N = $\frac{10^{24}}{10^{11}}$

N = $10^{24 - 11} = 10^{13}$

The number of galaxies in the universe is approximately $10^{13}$ .

7 0

3 years ago

When 5x^2 + 2= 4x is written in standard form, what are the values of a, b, and c

goblinko [34]

The standard form of a quadratic equation is

$ax^{2}+bx+c=0$ ,

where $a$ , $b$ , and $c$ are coefficients. You want to get the given equation into this form. You can accomplish this by putting all the non-zero values on the left side on the equation.

In this case, the given equation is

$5x^{2}+2=4x$

Since $4x$ is on the right side of the equation, we subtract that from both sides. The resulting equation is

$5x^{2}-4x+2=0$

Looking at the standard form equation $ax^{2}+bx+c=0$ , we can see that

$a=5, b=-4, c=0$

7 0

3 years ago

Can you find the mean for these two questions:

Molodets [167]

1) Mean Absolute Deviation = 1.75

2) Mean = 244

7 0

4 years ago

Read 2 more answers