Answer:
Third option, letter c
Explanation:
3/8 are male, so the chance for 1 year is 3/8
Then for 2 years in a row, the chance decreases, so it is: 3/8.3/8=9/64 or (3/8)^2
Hope you get it!
Answer:
The answer is 38
Step-by-step explanation:
Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
Answer:
Graph C shows the solution for the inequality
Step-by-step explanation:
y - 4 > 2(x + 2)
y > 2x + 4 + 4
y > 2x + 8
Let y = 2x + 8, Then
X-intercept (0, 8)
Y-intercept (-4, 0)
Since the inequality sign is > we use broken line.
Put, (0, 0)
y > 2x + 8
0 > 0+ 8
0 > 8 Which is false
so, the answer will be above the broken line
Hence , Graph C shows inequality
#SPJ1
Answer:

General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]: ![\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Integration
Integration Rule [Fundamental Theorem of Calculus 1]: 
Integration Property [Multiplied Constant]: 
U-Substitution
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Integrate Pt. 1</u>
<em>Identify variables for u-substitution.</em>
- Set <em>u</em>:

- [<em>u</em>] Differentiate [Basic Power Rule, Derivative Properties]:

- [Bounds] Switch:

<u>Step 3: Integrate Pt. 2</u>
- [Integral] Rewrite [Integration Property - Multiplied Constant]:

- [Integral] U-Substitution:

- [Integral] Exponential Integration:

- Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:

- Simplify:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration