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avanturin [10]
2 years ago
6

How do I find a percentage from a discount​

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
5 0

Answer:

Subtract the post-discount price from the pre-discount price.

Divide this new number by the pre-discount price.

Multiply the resultant number by 100.

Step-by-step explanation:

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Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards. If the actual width of a neighborhood park is 62 yard
klemol [59]

Answer:

The park is <u>31 inches</u> wide in the drawing.

Step-by-step explanation:

Given:

Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.

The actual width of a neighborhood park is 62 yards.

Now, to find the width of park in drawing.

Let the width of park in drawing be x.

The scale drawing of the city is 1 inch : 2 yards.

So, 1 inch is equivalent to 2 yards.

Thus, x is equivalent to 62 yards.

Now, to get the width of park in drawing by using cross multiplication method:

\frac{1}{2} =\frac{x}{62}

By cross multiplying we get:

62=2x

Dividing both sides by 2 we get:

31=x

x=31\ inches.

Therefore, the park is 31 inches wide in the drawing.

8 0
2 years ago
Jayden invested $22,000 in an account paying an interest rate of 2.5% compounded
Gemiola [76]

Answer:

12.9

Step-by-step explanation:

30400=

30400=

\,\,22000e^{0.025t}

22000e

0.025t

Plug in

\frac{30400}{22000}=

22000

30400

​

=

\,\,\frac{22000e^{0.025t}}{22000}

22000

22000e

0.025t

​

Divide by 22000

1.3818182=

1.3818182=

\,\,e^{0.025t}

e

0.025t

\ln\left(1.3818182\right)=

ln(1.3818182)=

\,\,\ln\left(e^{0.025t}\right)

ln(e

0.025t

)

Take the natural log of both sides

\ln\left(1.3818182\right)=

ln(1.3818182)=

\,\,0.025t

0.025t

ln cancels the e

\frac{\ln\left(1.3818182\right)}{0.025}=

0.025

ln(1.3818182)

​

=

\,\,\frac{0.025t}{0.025}

0.025

0.025t

​

Divide by 0.025

12.9360062=

12.9360062=t

t = 12.9

12.9

3 0
3 years ago
When constructing inscribed polygons and perpendicular lines how are the steps similar
bagirrra123 [75]
When constructing inscribed polygons and perpendicular lines, how are the steps similar?
<span>There are no similarities.</span>
8 0
3 years ago
4
Maru [420]

First, we have to understand the slope-intercept form.

\large \boxed{y = mx + b}

A linear function/equation has three forms and the slope-intercept is one of the form. It is also commonly used in Function topic while the other two forms are commonly used in Analytic Geometry.

In the slope-intercept form, the m-term represents the slope while b-term represents the y-intercept of a graph.

<em>W</em><em>h</em><em>i</em><em>c</em><em>h</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>r</em><em>e</em><em>p</em><em>r</em><em>e</em><em>s</em><em>e</em><em>n</em><em>t</em><em>s</em><em> </em><em>a</em><em> </em><em>l</em><em>i</em><em>n</em><em>e</em><em>a</em><em>r</em><em> </em><em>f</em><em>u</em><em>n</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>h</em><em>a</em><em>s</em><em> </em><em>a</em><em> </em><em><u>s</u></em><em><u>l</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>5</u></em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>a</em><em> </em><em><u>y</u></em><em><u>-</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>e</u></em><em><u>r</u></em><em><u>c</u></em><em><u>e</u></em><em><u>p</u></em><em><u>t</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>-</u></em><em><u>6</u></em><em><u>.</u></em>

As you notice the bold, italic and underlined words in the question that I quoted or rewrote. I've just explained that the slope is m-term and y-intercept is b-term.

Therefore, substitute m = 5 and b = -6 in the equation.

\large{y = mx + b \longrightarrow \bold{y = 5x + ( - 6)}} \\  \large \boxed{ \tt{ \purple{y = 5x - 6}}}

I hope this helps! Let me know if you have any questions regarding the linear function, don't hestitate to ask. Good luck with your assignment and have a nice day!

5 0
2 years ago
What is the probability
vovangra [49]
True is the answer imo
5 0
2 years ago
Read 2 more answers
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