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3 years ago

Which of the follow is is trinomial

Mathematics

2 answers:

sasho [114]3 years ago

6 0

Answer:

A. 3x^2 + 4x + 1

Step-by-step explanation:

A is the correct answer because there are three terms within the trinomial

kaheart [24]3 years ago

3 0

Answer:

A. 3x^2 + 4x + 1

Step-by-step explanation:

Option A. is a trinomial because it is a polynomial with 3 terms.

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100 points + brainlest please help due today

Reptile [31]

Answer:

Use the formula for direct variation

Step-by-step explanation:

6 0

3 years ago

3. Suppose that you draw two cards from a standard 52 card deck. You replace the first card and shuffle thoroughly before you dr

Kruka [31]

Answer:

$\text{a)} \frac{1}{17} \text{b)} \frac{1}{221}\text{c)}\frac{12}{13}\text{d)}\frac{188}{221}$

Step-by-step explanation:

GIVEN: You draw two cards from a standard $52$ card deck. You replace the first card and shuffle thoroughly before you draw the second.

TO FIND: a) What is the probability that the first card is $7$ b) What is the probability that both cards are

SOLUTION:

Let $\text{A}$ and $\text{B}$ be two events such that

$\text{A}$ $=\text{first card drawn is 7}$

$\text{B}$ $=\text{Second card is 7}$

$\text{probability that first card is 7 =P(A)}$

<h3> $\text{P(A)}=\frac{\text{total 7 numbered cards}}{\text{total cards in deck}}$ </h3><h3> $\text{P(A)}=$ $\frac{4}{52}=\frac{1}{13}$ </h3>

$\text{probability that first card is 7 =P(A)}$

$\text{probability that both cards are 7}=$ $\text{first card is 7}\times\text{second card is 7}$

$\text{probability that both cards are 7}=$ $\text{P(A).P(B)}$

$\text{P(B)}=\frac{\text{total number of 7 numbered cards left}}{\text{total number of cards in deck left}}$

$\text{P(B)}=\frac{3}{51}=\frac{1}{17}$

$\text{probability that both cards are 7}=$ $\frac{1}{13}\times\frac{1}{17}$

$\text{probability that both cards are 7}=$ $\frac{1}{221}$

$\text{probability that first card is not 7}=1-\text{probability that first card is 7}$

$\text{probability that first card is not 7}=$ $1-\text{P(A)}$

$\text{probability that first card is not 7}=$ $1-\frac{1}{13}$

$\text{probability that first card is not 7}=$ $\frac{12}{13}$

$\text{probability that both cards are not 7}=$ $(\text{first card is not 7}).(\text{second card is not 7})$

$\text{probability that both cards are not 7}=$ $\text{[1-P(A)].[1-P(B)]}$

$\text{P(B)}=\frac{\text{total 7 numbered cards}}{\text{total cards left in deck}}$

$\text{probability that both cards are not 7}=$ $(1-\frac{1}{13})\times(1-\frac{4}{51})$

$\text{probability that both cards are not 7}=$ $\frac{12}{13}\times\frac{47}{51}$

8 0

3 years ago

mary bought 4 1/4 pounds of grapes and 5 3/4 pounds of cherries. he paid $1.34 a pound for the grapes and $1.74 a pound for the

Dmitry_Shevchenko [17]

He paid 5.695 for the grapes and 10.005 for the cherries. The answer is he paid $4.31 more for the cherries.

6 0

4 years ago

Answer each question with work and reasoning

slavikrds [6]

Answer:

Step-by-step explanation:

2 + 3 = 6

6 x 10 = 30

30 snowmen

3 0

3 years ago

Find the missing side lengths leave your answerss as radicals

Phoenix [80]

Answer:

n=7

m= 7 $\sqrt{3}$

Step-by-step explanation:

lmk if you need work

7 0

3 years ago