Remember that mixed fractions are equivalent to the sum of the whole number and the fraction. Thus, we can start by simplifying the mixed fraction like so:
![14 \dfrac{52}{60} = 14 + \dfrac{52}{60} = \dfrac{892}{60} Now, realize that both 892 and 60 have a common factor of 4, which means that we can divide both the numerator and the denominator by 4. This gives us:[tex]\dfrac{892 \div 4 }{60 \div 4} = \dfrac{223}{15}](https://tex.z-dn.net/?f=14%20%5Cdfrac%7B52%7D%7B60%7D%20%3D%2014%20%2B%20%5Cdfrac%7B52%7D%7B60%7D%20%3D%20%5Cdfrac%7B892%7D%7B60%7D%3C%2Fp%3E%20%3Cp%3ENow%2C%20realize%20that%20both%20892%20and%2060%20have%20a%20common%20factor%20of%204%2C%20which%20means%20that%20we%20can%20divide%20both%20the%20numerator%20and%20the%20denominator%20by%204.%20This%20gives%20us%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cdfrac%7B892%20%5Cdiv%204%20%7D%7B60%20%5Cdiv%204%7D%20%3D%20%5Cdfrac%7B223%7D%7B15%7D)
Thus, 14 52/60 simplifies to 223/15.
Step-by-step explanation:
the square of 12 =12×12 =144
and the square root of 196324 = ✓196324
= 443.084642
Hi! You don't actually need to graph this nor find the intersection in order to know the answer. Through the process of elimination we can rule out incorrect answers.
Firstly, we express both equations with y on the left hand side since all choices are in that form:


Knowing these, we can immediately rule out options a, c, and d since they have the wrong equations. This will leave us with option b.
You can verify if the point of intersection provided in option b is true by plugging in the values of x and y to both equations (you will find that it is indeed true).
ANSWER: b. <span>picture of coordinate plane with line y equals negative 2x minus 1 and line y equals negative 3 halves x minus 3. They intersect at 4, negative 9.</span>
Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed