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3 years ago

Write an equation that represents the line

Mathematics

2 answers:

Savatey [412]3 years ago

4 0

Answer:

y = -1/2 x - 3.5

Step-by-step explanation:

y = mx+ b

m is the slope of the line

m = -1/2

b is the y-intercept

b = -3.5

Pie3 years ago

3 0

Answer:

y=(-1/2)x-3.5

Step-by-step explanation:

Using the equation (rise/run) with the two marked points, we find that the slope is (1/-2), or -1/2.

The y-intercept, as seen in the graph, is -3.5.

Once you plug the slop and y-intercept into y=mx+b, you get your equation: y=(-1/2)x-3.5

To check your answer, swap x and y out for values of a point on the line. With the point (1, -4)..:

-4=(-1/2)1-3.5

-4=(-1/2)-3.5

-4=-4

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Answer:

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Step-by-step explanation:

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3 years ago

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2 years ago

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The formula for the circumference of a circle is C = 2 πr .use this formula for RADIUS of a circle

Luden [163]

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3 years ago

Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random

lesya692 [45]

Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes $P_B(A)$ .

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
$P(A|B)= \frac{P(A \cap B)}{P(B)}$

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is $\frac{1}{3}$

Part A:
To find the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus $P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}$

P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

Thus $P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$

Therefore, $P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}$

Part B:
To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.

$P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}$

 $P(D)= \frac{1}{3}$ 

Therefore, $P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}$

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3 years ago