Answer:
Step-by-step explanation:
From the given information:
ΔG° = -30.5 kJ/mol
By applying the following equation to calculate the value of K.
ΔG° =-RT㏑K
making ㏑ K the subject of the formula:
where;
Temperature at 25° C = (25 + 273)K
= 298K
R = 8.3145 J/mol.K (gas cosntant)
㏑K = 12.309
K = 221682.17
K = 2.22 × 10⁵
b) The reaction for the metabolism of glucose is given as:
From the above expression, let calculate the Gibbs free energy by using the formula:
At standard conditions;
The values of corresponding compounds are substituted into the equation above:
Thus,
Now, the no of ATP molecules generated =
= (-2875000 J/mol ) / -30500 J/mol
= 94.26
≅ 94 ATP molecules generated