Ask question

Ask question

All categories

2 years ago

12

I HAVE 5 MINS PLZ HELP!

1 answer:

White raven [17]2 years ago

8 0

7/6
it’s positive because it’s going up

You might be interested in

What is the area of this trapezoid? Enter your answer in the box.

mezya [45]

Answer:

352 ft²

Step-by-step explanation:

The formula for the area of a trapezoid is $A=(\frac{b_1+b_2}{2})h$ where $b_1$ and $b_2$ are the bases of the trapezoid and $h$ is the height, thus:

$A=(\frac{b_1+b_2}{2})h\\\\A=(\frac{13+31}{2})(16)\\\\A=(\frac{44}{2})(16)\\ \\A=(22)(16)\\\\A=352$

This means that the area of the trapezoid is 352 ft².

5 0

2 years ago

a trapezoid with an area of 166.75 in has bases that measure 21in and 8 in find the height of the trapezoid

alisha [4.7K]

Answer:

height = 11.5 in

Step-by-step explanation:

The area (A) of a trapezoid is calculated using the formula

A = $\frac{1}{2}$ h(a + b)

where h is the height and a, b the bases

here a = 21, b = 8 and A = 166.75, hence

$\frac{1}{2}$ h(21 + 8) = 166.75

Multiply both sides by 2 to eliminate the fraction

29h = 333.5 ( divide both sides by 29 )

h = 11.5 in

6 0

2 years ago

What mathematicians helped to discover alternatives to euclidean geometry in the nineteenth century

Likurg_2 [28]

Answer:

Nikolai Lobachevsky and Bernhard Riemann

Step-by-step explanation:

Nikolai Lobachevsky (A russian mathematician born in 1792) and Bernhard Riemann (A german mathematician born in 1826) are the mathematicians that helped to discover alternatives to euclidean geometry in the nineteenth century.

7 0

2 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

2 years ago

PLEASE HELP URGENT!!!! Can someone plss help me with these!!

lana66690 [7]

Answer:

ok who are 38 no butplease

4 0

2 years ago