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Kitty [74]
2 years ago
12

(4p-4)+(-7p-7) I need HELP ON THIS PLEASE FAST!!

Mathematics
1 answer:
yuradex [85]2 years ago
8 0

Answer:

The correct answer is number 2

-3p - 11

I'm 1000000% sure...

You might be interested in
Limit   
STatiana [176]

Rationalize the numerator:

\dfrac{\sqrt{x+4}-2}x\cdot\dfrac{\sqrt{x+4}+2}{\sqrt{x+4}+2}=\dfrac{(\sqrt{x+4})^2-2^2}{x(\sqrt{x+4}+2)}=\dfrac x{x(\sqrt{x+4}+2)}=\dfrac1{\sqrt{x+4}+2}

This is continuous at x=0, so we can evaluate the limit directly by substitution:

\displaystyle\lim_{x\to0}\frac{\sqrt{x+4}-2}x=\lim_{x\to0}\frac1{\sqrt{x+4}+2}=\frac1{\sqrt4+2}=\frac14

5 0
3 years ago
A cognitive psychologist would like to evaluate the claim that the omega-3 fatty acids can help improve memory in normal adult h
bogdanovich [222]

Answer:

(a)

  • Independent Variable- Dosage of Omega-3 Fatty Acids
  • Dependent Variable - Number of news item remembered

(b)Discrete

(c)Ratio Scale and Discrete Variable

(d) Experimental Method

Step-by-step explanation:

The psychologist wants to evaluate the claim that omega-3 fatty acids can help improve memory in normal adult humans.

(a)In the study, the participants in the two groups were given fish extracts containing Omega-3 (500 mg) and no Omega-3 (0 mg).

The memory test involves measuring the number of items each participant remembers from the past three weeks of news.

Therefore:

  • Independent Variable- Dosage of Omega-3
  • Dependent Variable - Number of news item remembered

(b) The dependent variable is discrete since the number of news items remembered can only be whole numbers.

(c)The independent variable is in milligrams of Omega-3 where the placebo is 0 mg. This is a ratio scale since it has an absolute zero.

Since the dosage is given in multiples of 50mg, it is a discrete variable.

(d)Since the psychologist seeks to manipulate the conditions of the study by introducing Omega-3 to some of the participants and placebo to other participants, it is an experimental distribution.

5 0
2 years ago
Find lim x->2 for f(x)=
TiliK225 [7]

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

8 0
1 year ago
Question 5. How do I find the answer? I am lost
Svetach [21]
Easy, its b because that is the average deviation

6 0
3 years ago
What is the equivalent decimal of 14 14/20
Fynjy0 [20]
Two parts there: 14 the integer and 14/20, a fraction which needs to be converted to decimal.

14/20 = 7/10=0.7

combining, the ans is 14.7

4 0
3 years ago
Read 2 more answers
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