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3 years ago

6

(Algebra 2) write a polynomial function of least degree with integral coefficients that has the given zeros.

1 answer:

saveliy_v [14]3 years ago

6 0

Answer:

$x^{2} -2ix+3=0$ .

Step-by-step explanation:

Given the zeroes of the polynomial are

a=-i . and b=3i

The recquired polynomial is $(x-a)(x-b)=0$

On substituting the values of a and b we get

$(x+i)(x-3i)=0$

$x^{2} -3xi+ix-3i^{2}=0$

$x^{2} -2ix+3=0$ . (∵ $i^{2}=-1$ )

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Answer:

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Answer:

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Step-by-step explanation:

Please find the correct question in the attached file:

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