Answer:
FIGURE 1:
x = 118; y = 96
FIGURE 2:
x = 85; y = 65
Step-by-step explanation:
FIGURE 1:
You know that x = 118 because of the Corresponding Angles theorem.
Because of the Exterior Angle Theorem (triangles), you can then figure out what y is with the following equation: y + 22 = 118 to get y = 96.
FIGURE 2:
In this figure, you first need to determine what the third angle in the bottom right triangle is. Using the Triangle Sum Theorem, you would find that the third angle is 70.
Because of the Vertical Angles Theorem, you know that the third angle in the top left triangle is also 70. With this information, you can now solve for x using the Triangle Sum Theorem to get x = 85.
Now that you know x, you can solve for y. The other 3 angles in the quadrilateral in which y is a part of are 90, 110, and 95. These could be figured out using the Linear Pair Postulate, the Vertical Angles Theorem, and the Linear Pair Postulate respectively. Now you can figure out y by using the Quadrilateral Sum Conjecture to get y = 65.
3:8 - 3:8
8:6 - 4:3
4:8 - 1:2
I would say that the answer is 1:2
9514 1404 393
Answer:
205 ft
Step-by-step explanation:
Let w represent the width of the rectangle. Then the length is (6w-17) and the area is ...
A = LW
7585 = (6w-17)(w)
6w² -17w -7585 = 0
Perhaps most straightforward is using the quadratic formula to solve this.
For ax² +bx +c = 0, the solution is x = (-b±√(b²-4ac))/(2a). For the above quadratic, the solution is ...
The width is 37 feet, so the length is ...
6(37) -17 = 205 . . . feet
The length of the rectangle is 205 feet.
Answer:
The answer is 14!
Step-by-step explanation:
Answer:
find the value of x that makes the denominator zero: x = 7
Step-by-step explanation:
A vertical asymptote shows up where the denominator is zero. As the denominator gets closer to zero, the function value gets larger without bound (unless there is a numerator factor that cancels the one in the denominator).
To find the value of x at the vertical asymptote, solve the equation ...
denominator = 0
x - 7 = 0
x = 7 . . . . . . . add 7 to both sides