1−w−w2=64
Step 1: Simplify both sides of the equation.
−w2−w+1=64
Step 2: Subtract 64 from both sides.
−w2−w+1−64=64−64
−w2−w−63=0
For this equation: a=-1, b=-1, c=-63
−1w2+−1w+−63=0
Step 3: Use quadratic formula with a=-1, b=-1, c=-63.
w=
−b±√b2−4ac
/2a
w=
−(−1)±√(−1)2−4(−1)(−63)
/2(−1)
w=
1±√−251/
−2
I think 54 is the answer of this puestion
9+10=19
proof, 9=1 plus 1 9 times (to lazy to write it out)
10=1 plus 1 10 times(to lazy)
so 1+1+1+1+1+1+1+1+1 + 1+1+1+1+1+1+1+1+1+<span>1 = 19</span>
Using the midpoint formula, the coordinates of the intersection of the diagonals of the parallelogram is: (1, 2.5).
<h3>What are Diagonals of a Parallelogram?</h3>
The diagonals of a parallelogram bisect each other, therefore, the coordinates of their intersection can be determined using the midpoint formula, which is: 
.
A diagonal is XZ.
X(2, 5) = (x1, y1)
Z(0, 0) = (x2, y2)
Plug in the values
= (1, 2.5).
Learn more about the diagonals of a parallelogram on:
brainly.com/question/12167853
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To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
