A=P (1+r/n)^nt
A= Total amount invested, P=principal amount, r=Interest rate, n=number of time in a year when the interest is earned (for annual, n=1; for semi-annual, n=2, ...), t = time in years
In the current scenario, case 1, n=2; case 2, n=1 and A1=A2, t1=t2
Therefore,
800(1+0.0698/2)^2t = 1000(1+0.0543/1)t
Dividing by 800 on both sides;
(1+0.0349)^2t = 1.25(1+0.02715)^t
(1.0349)^2t = 1.25(1.02715)^t
Taking ln on both sides of the above equation;
2t*ln (1.0349)= ln 1.25 + t*ln (1.02715)
2t*0.0343 = 0.2231+ t*0.0268
0.0686 t = 0.2231+0.0268 t
(0.0686-0.0268)t = 0.2231
0.0418t=0.2231
t=5.337 years
Therefore, after 5.337 years or 5 years and approximately 4 months, their value of investments will be equal.
This value will be,
A=800(1+0.0698/2)^2*5.337 = $1,153.76
Answer:
The correct option is (D).
Step-by-step explanation:
Percentiles are statistical measures that are used to interpret data. It represents the data value which is more that a specific percentage of the data set.
The <em>n</em>th percentile of a data set is the value that is more that <em>n</em>% of the data set.
⇒ It is provided that a test-taker's score was at the 94th percentile for their verbal grade.
This statement implies that the test taker scored a mark more than 94% of the other test-takers, i.e. he\she performed better than 94% of the other test-takers in the verbal grade.
⇒ Also the test-taker's score was at the 16th percentile for their quantitative grade.
This implies that the test taker scored a mark more than 16% of the other test-takers, i.e. he\she performed better than 16% of the other test-takers in the quantitative grade.
Thus, the correct option is (D).
Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .
Rule: (x, y)→(x + 8, y + 1 )
J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)
J’ (6,3)
K’ (5,-3)
L’ (9,-1)
Hope this helps!
Answer:
an+4n+1
Step-by-step explanation:
Hope it helped
