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bearhunter [10]
3 years ago
6

Which calculation correctly uses prime factorization to write V48 in simplest form?

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

C

\sqrt{48}  =  \sqrt{2 \times 2 \times 2 \times 2 \times 3}  \\  =  \sqrt{16 \times 3}   \\  = 4 \sqrt{3}

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In 0.73, in which place is the 0
Svetllana [295]

Answer:

The digit '0' is in the ones place.

6 0
3 years ago
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What is the volume of the rectangular prism?
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B is the answer have a g00d day

3 0
4 years ago
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Prove this <br><br> 1-tan^2x/1+tan^2x=cos^2x-sin^2x
tatiyna

Answer:

see explanation

Step-by-step explanation:

Using the identity

tan x = \frac{sinx}{cosx}

Consider the left side

\frac{1-tan^2x}{1+tan^2x}

= \frac{1-\frac{sin^2x}{cos^2x} }{1+\frac{sin^2x}{cos^2x} } ( multiply numerator and denominator by cos²x to clear fractions

= \frac{cos^2x-sin^2x}{cos^2x+sin^2x} ← ( cos²x + sin²x = 1 ]

= cos²x - sin²x

= right side , thus proven

7 0
3 years ago
F(x)=√4x+6 g(x)= √4x-6 find (f+g)(x)
e-lub [12.9K]

Answer:

(f+g)(x) = √(4x+6) + √(4x-6)

Step-by-step explanation:

f(x) = √(4x+6)

g(x) = √(4x-6)

(f+g)(x) = f(x) + g(x)

(f+g)(x) = √(4x+6) + √(4x-6)

4 0
4 years ago
What is the area of a triangle whose vertices are (4,0), (2,
yan [13]

Answer:

The correct option is;

b) 0 sq, units

Step-by-step explanation:

The vertices of the triangle are;

(4, 0), (2, 3), (8, -6)

The distance formula fr finding the length of a segment is given as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where, (x₁, y₁) and (x₂, y₂) are the coordinates of the end points of the line

For the points (4, 0) and (2, 3) , we have;

√((3 - 0)² + (2 -4)²) = √13

Distance from (4, 0) to (2, 3) = √13

For the points (4, 0) and (8, -6) , we have;

√((-6 - 0)² + (8 -4)²) = √13 =

Distance from (4, 0) to (8, -6) = 2·√13

For the points (2, 3) and (8, -6) , we have;

√((-6 - 3)² + (8 -2)²) = 3·√13 =

Distance from (2, 3) to (8, -6) = 3·√13

Therefore, the perimeter of the triangle = 6·√13

The semi perimeter s = 3·√13

The area of the triangle,  A  = \sqrt{s\cdot \left (s-a  \right )\cdot \left (s-b  \right ) \cdot \left ( s-c  \right )}

Where;

a, b, and c are the length of the sides of the triangle;

A  = \sqrt{3\cdot \sqrt{3} \cdot \left (3\cdot \sqrt{3} -\sqrt{3}   \right )\cdot \left (3\cdot \sqrt{3} -2 \cdot \sqrt{3}   \right ) \cdot \left ( 3\cdot \sqrt{3} -3\cdot \sqrt{3}   \right )} = 0

Therefore, the area = 0 sq, units.

6 0
4 years ago
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