Step-by-step explanation:
but sorry i can't get the answer of (2x-1) =3 (x+5) because the answer of this came -16
So the answers are :
A: 5 seconds
and
B: 10 seconds
Answer:
(a) 218.6 N
(b) 97.14 N
Step-by-step explanation:
When the system is in equilibrium, the net torque on the system is zero.
AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m
Let the centre of gravity of plank is at G.
AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m
(a) Let the reaction at C is R and at D is R'.
R + R' = 29 x 9.8 = 284.2 N ... (1)
Take the torque about C.
29 x 9.8 x CG = R' x GD
29 x 9.8 x 1 = R' x 1.3
R' = 218.6 N
(b) Take the torque about D.
6 x 9.8 x AD = R x CD
6 x 9.8 x (1.5 + 2.3) = R x 2.3
R = 97.14 N
1. You'll need to download this data, or copy it down by hand.
2. Rearrange the data from lowest to highest values.
3. You have 24 data points (an even number).
In this case, to find the 1st quadrant, take the left half (that is, the left 12) data points. Since 12 is an even number, you must find the average of the middle two of these 12 data points. Your result is the 1st quadrant.
To find the 3rd quadrant, find the middle two data points of the right-hand 12 data points. Average these two points. The result is the 3rd quadrant.
