Question

Instructions: Identify the type of sequence and write the recursive rule.

Answer 1

Answer:

$a_n=a_{n-1}+8,n\geq 1$

$a_1=-11$

Step-by-step explanation:

We are given that a sequence

-11,-3,5,13,...

$a=a_1=-11$

$a_2=-3$

$a_3=5$

$a_2-a_1=-3-(-11)=-3+11=8$

$a_3-a_2=5-(-3)=5+3$

$a_3-a_2=8$

Common difference between two consecutive terms is equal.

Hence, the sequence is Arithmetic.

Common difference, d=8

$a_2=a_1+8=-3$

$a_3=a_2+8=5$

$a_4=a_3+8=13$

:

:

:

$a_n=a_{n-1}+8, n\geq 1$

$a_1=-11$