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Hunter-Best [27]
3 years ago
15

Answer needed -3x + 9 = 18

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

X=-3

Step-by-step explanation:

Is that what you need?

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John has 8 cards that spell the word H O M E W O R K. She shuffles them and then places them face down. Assume she returns the c
finlep [7]

Answer:

The probability that I will choose a consonant is 62.50%.

Step-by-step explanation:

Given that John has 8 cards that spell the word H O M E W O R K, and he shuffles them and then places them face down, to determine what is the probability he will choose a consonant the following calculation must be performed:

Vowels: 3

Consonants: 5

5/8 = X

0.625 = X

0.625 x 100 = 62.50

Therefore, the probability that I will choose a consonant is 62.50%.

3 0
2 years ago
Determine the slope of the line passing through (-8,-5) and (-10,-9)
nikklg [1K]

Answer:

2

Step-by-step explanation:

y1-y2/x1-x2

6 0
2 years ago
Read 2 more answers
What is the image of ( − 5 , 4 ) (−5,4) after a reflection over the line y = x y=x?
balandron [24]

Answer:

(4,−5)

Step-by-step explanation:

7 0
2 years ago
I need help w/ this!! thank you
Fittoniya [83]
<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
4 0
2 years ago
Write a parallel and perpendicular equation that passes through the point (6,-2)?
Reptile [31]

Answer:

y=x-8 and y=-x+4

Step-by-step explanation:

The slopes of the lines can be anything, as long as they are the opposite reciprocals of each other. Then you can plug in the point for x and y to solve for b in both lines (for y=mx+b where m is the slope)

3 0
3 years ago
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