<h3>
Answer: 21</h3>
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Work Shown:
The diagram shows that JK = 12 and GF = 2.5*(JK) = 2.5*12 = 30
The midsegment HL will be the average of the two lengths it is parallel to.
We'll add up the values and then cut the result in half
HL = (JK+GF)/2
HL = (12+30)/2
HL = 42/2
HL = 21
X=4
cross multiply
3x=12
x=4
F(2) = 3(2)^2 + 2(2) + 4
= 3(4) + 4 + 4
= 12 + 8
f(2) = 20
f(a+h) = 3(a+h)^2 + 2(a+h) + 4
= 3(a^2 + 2ah + h^2) + 2a + 2h + 4
f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4
Answer:
x=1
Step-by-step explanation:
1 is B
2 is C
3 is A
4 is E
It's a simple question if you use the graph. I recommend you plot the points, so hopefull you can see how i got the answers.
