x is the 1st number, y is the 2nd number, z is the 3d number.
x+y+z = 2
x - y + z= -2
x - z = y +22 -----> x-y-z=22
x+y+z = 2
<u>x - y + z= -2</u>
2x + 2z =0
x + z = 0
x = -z
x - y + z= -2 and x = -z
-z - y + z = -2, y =2
x-y-z=22 and x = -z, and y = 2 -----> x -2 +x = 22 --->2x = 24 ----> x = 12
x= -z -----> z = - 12
Answer:
37 and 27
Step-by-step explanation:
Lets say that the two numbers are x and y. We get the equations x + y = 64 and x - y = 10. We can then add these two equations together to get, 2x = 74. Then we divide by two on both sides and get x = 37. We then plug this value back into the second equation and get that 37 - y = 10. We can simplify this and we get that y = 27. So our two numbers are 37 and 27.
Let's solve your system by substitution.
y
=
−
2
x
+
7
;
y
=
5
x
−
7
Step: Solve
y
=
−
2
x
+
7
for y:
y
=
−
2
x
+
7
Step: Substitute
−
2
x
+
7
for
y
in
y
=
5
x
−
7
:
y
=
5
x
−
7
−
2
x
+
7
=
5
x
−
7
−
2
x
+
7
+
−
5
x
=
5
x
−
7
+
−
5
x
(Add -5x to both sides)
−
7
x
+
7
=
−
7
−
7
x
+
7
+
−
7
=
−
7
+
−
7
(Add -7 to both sides)
−
7
x
=
−
14
−
7
x
−
7
=
−
14
−
7
(Divide both sides by -7)
x
=
2
Step: Substitute
2
for
x
in
y
=
−
2
x
+
7
:
y
=
−
2
x
+
7
y
=
(
−
2
)
(
2
)
+
7
y
=
3
(Simplify both sides of the equation)
Answer: x=2 and y=3
