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Alenkinab [10]
3 years ago
11

Which statement regarding triangle EFG are true? Select three options

Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

It is the first three options. A,B,C or 1,2,3

Step-by-step explanation:

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Kim has a $10 bill, a $20 bill, and 2 $5 gift certificates. she uses the gift certificates toward the purchase of a cd for $14.0
uysha [10]

When Has $26 Left !!

8 0
3 years ago
A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take
Pani-rosa [81]

Answer:

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  sample mean (x⁻ )  = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

<em>Null Hypothesis :- H₀ :  </em> (μ) =500

Alternative Hypothesis : H₁ :  μ ≠ 500

<u><em>Step(ii)</em></u>:-

Test statistic

                         t = \frac{x^{-} -mean}{\frac{s}{\sqrt{n} } }

                        t = \frac{517 -500}{\frac{90}{\sqrt{100} } }

                        t  =   1.717

<em>Level of significance</em>

                      ∝ = 0.05

                    t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

<u><em>Conclusion</em></u>:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

3 0
3 years ago
20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
P2m divied 4; use m =9 and p=3
yulyashka [42]
The answer to your question is 13.2
4 0
3 years ago
a school paid $31.50 for each calculator, if the school spent 504 dollars on calculators how many did the school buy?​
monitta
The school bought 16 calculators.


504/31.50 =16
7 0
3 years ago
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