Solution: The given problem is a binomial distribution.
The probability that a team member receives a scholarship is 
Therefore, the given problem follows binomial with n = 5 and p = 0.6667
Now the probability that 4 of 5 players selected are on scholarship is:



Therefore, the probability that 4 of 5 players selected are on scholarship is 0.329
The answer is 9.48. also I rounded
The irrational in between should be 7.8
Step-by-step explanation:
2(x+4) = 12
or, 2x + 8 = 12
or, 2x = 12-8
or, 2x = 4
or, x = 4÷2
hence, x = 2
Answer:
Now if the high and low monthly average temperatures satisfy the inequality, then the , monthly averages are always within 22 degrees of 43°F.
Step-by-step explanation:
The inequality describes the range of monthly average temperatures T in degrees Fahrenheit at a certain location.
The inequality expression is given as:

now this expression could also be expressed as:

Now if the high and low monthly average temperatures satisfy the inequality, then the , monthly averages are always within 22 degrees of 43°F.
( As the difference is 22 degrees to the left and right)