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Brrunno [24]
3 years ago
6

In this problem, we explore the effect on the standard deviation of adding the same constant to each data value in a data set. C

onsider the following data set.
8, 16, 14, 8, 16

(a) Use the defining formula, the computation formula, or a calculator to compute s. (Enter your answer to four decimal places.)

(b) Add 8 to each data value to get the new data set 16, 24, 22, 16, 24. Compute s. (Enter your answer to four decimal places.)

(c) Compare the results of parts (a) and (b). In general, how do you think the standard deviation of a data set changes if the same constant is added to each data value?

Adding the same constant c to each data value results in the standard deviation remaining the same.

Adding the same constant c to each data value results in the standard deviation increasing by c units.

Adding the same constant c to each data value results in the standard deviation decreasing by c units.

There is no distinct pattern when the same constant is added to each data value in a set.

Mathematics
1 answer:
aliya0001 [1]3 years ago
6 0

Answer:

3.6661

3.6661

A, Adding a constant does nothing to the standard deviation

Step-by-step explanation:

I'm gonna assume s=standard deviation

The standard deviation is just the square root of the second moment minus the first moment squared

Because we were not told otherwise I think it's pretty safe to assume that all events are equally likely

Let's start by calculating the first moment (AKA The mean)

1/5(8+16+14+8+16)= 12.4

Let's then find the second moment

1/5(8²+16²+14²+8²+16²)= 167.2

√(167.2-12.4²)=3.6661

b.

While I could just tell you that adding something to the standard deviation (and the variane as well) doesn't do anything let's calculate it for fun

same process

.2(16+24+22+16+24)= 20.4

.2(16²+24²+22²+16²+24²)=429.6

√(429.6-20.4²)= 3.6661

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5. A survey of student pizza preferences showed that 43 students preferred cheese, 56 preferred sausage, 39 preferred pepperoni,
cestrela7 [59]

Answer:

P (Cheese) = 0.199, P (Sausage) = 0.259, P (Pepperoni) = 0.181,

P (Supreme) = 0.130, P (Another Kind) = 0.144

and P (Does not like any kind) = 0.088

Step-by-step explanation:

Given:

Number of students who prefer cheese = 43

Number of students who prefer sausage = 56

Number of students who prefer pepperoni = 39

Number of students who prefer supreme = 28

Number of students who prefer another kind = 31

Number of students who did not like any kind = 19

∴ The total number of students surveyed = 43+56+39+28+31+19=216       The number of students who prefer pizza = 43+56+39+28+31=197

The probability that a students likes pizza is,

P(Student\ likes\ pizza)=\frac{No.\ of\ students\ who\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                     =\frac{197}{216} \\=0.912

The probability that a students does not likes pizza is,

P(Student\ does\ not\ likes\ pizza)=\frac{No.\ of\ students\ who\ does\ not\ prefer\ pizza}{Total\ no.\ of\ students\ surveyed}

                                                   =\frac{19}{216} \\=0.088

The probability distribution of students who prefer different kinds of pizza is:

  • The probability that a student likes cheese:

       P(A\ Student\ prefers\ cheese)=\frac{No.\ of\ students\ who\ prefer\ cheese}{Total\ no.\ of\ students\ surveyed}

                                                       =\frac{43}{216}\\=0.199

  • The probability that a student likes sausage:

        P(A\ Student\ prefers\ sausage)=\frac{No.\ of\ students\ who\ prefer\ sausage}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{56}{216}\\=0.259

  • The probability that a student likes pepperoni:

       P(A\ Student\ prefers\ pepperoni)=\frac{No.\ of\ students\ who\ prefer\ pepperoni}{Total\ no.\ of\ students\ surveyed}  

                                                             =\frac{39}{216}\\=0.181

  • The probability that a student likes supreme:

       P(A\ Student\ prefers\ supreme)=\frac{No.\ of\ students\ who\ prefer\ supreme}{Total\ no.\ of\ students\ surveyed}

                                                           =\frac{28}{216}\\=0.130

  • The probability that a student likes another kind:

        P(A\ Student\ prefers\ another\ kind)=\frac{No.\ of\ students\ who\ prefer\ another\ kind}{Total\ no.\ of\ students\ surveyed}

                                                                   =\frac{31}{216}\\=0.144

Thus, the probability distribution table is displayed below:

6 0
3 years ago
Solve each equation for p.<br> P+3/m=-1
Otrada [13]

Answer:

P= -m-3

I hope this helps!

3 0
3 years ago
63 is 90% of what number? In number line
Reika [66]
63/x=90/100
5670=100x
56.7
7 0
3 years ago
Nancy also has a mirror that measures 20.32 centimeters long. What is the length of Nancy’s mirror in inches?
tino4ka555 [31]

Answer:

C: 8.00

Step-by-step explanation:

1 in = 2.54 cm

l = 20.32 × 1/2.54

l = 8.00 in

The length of Nancy’s mirror is 8.00 in.

3 0
3 years ago
H = −8(3t − 3)(t + 2)
sergejj [24]

Answer

she be -5

Step-by-step explanation:

8 0
3 years ago
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