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insens350 [35]
2 years ago
11

PLEASE HELP!

Mathematics
1 answer:
Fed [463]2 years ago
8 0

Not sure for (b)

Step-by-step explanation:

(a)55+80+x=180 (angles inside the triangle)

135+×=+180

x=180-135

x=45

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What’s the correct answer for this question?
zhannawk [14.2K]

Answer:

D

Step-by-step explanation:

It would be a cone with a radius of 4 units rotating around y-axis.

6 0
3 years ago
Consider the following region R and the vector field F. a. Compute the​ two-dimensional curl of the vector field. b. Evaluate bo
Shalnov [3]

Looks like we're given

\vec F(x,y)=\langle-x,-y\rangle

which in three dimensions could be expressed as

\vec F(x,y)=\langle-x,-y,0\rangle

and this has curl

\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle

which confirms the two-dimensional curl is 0.

It also looks like the region R is the disk x^2+y^2\le5. Green's theorem says the integral of \vec F along the boundary of R is equal to the integral of the two-dimensional curl of \vec F over the interior of R:

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of R by

\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle

\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt

with 0\le t\le2\pi. Then

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt

=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0

7 0
3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
yan [13]

Answer:

  138.16 in²

Step-by-step explanation:

The surface area SA of the cone is the sum of the base area B and the lateral area LA. The lateral area is half the product of the circumference and the slant height. The radius is half the diameter, so is 4 inches.

  SA = B + LA

  = πr² + (1/2)(2πrh) . . . . where h is the slant height

  = (πr)(r +h)

Filling in the numbers, you have ...

  SA = (3.14)(4 in)(4 in + 7 in) = 3.14×(44 in²) = 138.16 in²

7 0
3 years ago
List all the multiples of 4 up to 20
emmainna [20.7K]
4 , 8 , 12 , 16 , 20
3 0
3 years ago
Please help my with this!!!!!!!!!!!!!!!!!!!!!!!!
butalik [34]

Answer:

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Step-by-step explanation:

5 0
2 years ago
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