Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
Answer:
56 degrees.
Step-by-step explanation:
We need the measure of < g.
The triangle formed by the 2 tangents and the chord is isosceles, because 2 tangents from a point outside a circle are of equal length (by the Two Tangents theorem).
Also one of the base angles are equal to 62 degrees ( by The Tangent Chord theorem). In fact both base angles are 62 degrees because the triangles an isosceles.
So measure of angle g = 180 - 2(62)
= 56 degrees.
Answer:
Y=-1/2x+4
Step-by-step explanation:
-The slope is -1/2 so you just plug it in where the slope would go with an x in front
-all you need now is your y-intercept which can be found by plugging in the provided info to your basic form y=mx+b
-You can take the provided point at (10,-1) and work out what the intercepts is
-1=-1/2(10)-b
-1=-5-b
4=b