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Illusion [34]
3 years ago
13

Can a denominator be negative in rational number?

Mathematics
2 answers:
SpyIntel [72]3 years ago
7 0

Answer: Rational Numbers are the Numbers where if p/q, q is not equal to 0 and p is an integer. So according to this questionm denominators can’t have the negative rational numbers. If it has, we need to convert it to standard form, eg:- p/-q = -p/q

Annette [7]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

A \ rational  \ number \ is  \ a \ number\ of\ the\ form\ \frac{p}{q}, \\\\where\ p\ and\ q \ are\  integers\  and\  q \ not\  equal \  to\  zero.\\\\That\ means\ q\ can\ take\ any\ number\ positive\ or\ negative\ but\ zero.

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Teagan is dividing 6 by 11. If she continues the process, what will keep repeating in the quotient?
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Answer:

54 will keep repeating in the quotient.

Step-by-step explanation:

Quotient is defined as the answer we get after dividing a number by another number. For instance 10 / 2 = 5. Here 10 is dividend, 2 is the divisor and 5 is the quotient.

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4 years ago
Help me do 1/6+1/4 make sure the demonator is the same
Alik [6]
<h2><u>Answer: </u></h2><h2> \boxed{\boxed{\sf\frac{5}{12}=0.416666667}}</h2><h2></h2><h2><u>Solution Steps: </u></h2>

______________________________

<h3>1.) Find the LCF of 6 and 4: </h3>
  • 6,4=12

<em>  - We do this because in order to add these, they must have the same denominator. So you must find the LCF, (Least Common Factor) of 6 and 4.</em>

<em />

<h3>2.) Convert the fractions to have the same denominator: </h3>
  • \frac{1}{6}=\frac{2}{12}
  • \frac{1}{4}=\frac{3}{12}

<em>  - </em>\frac{1}{6}<em> changes to </em>\frac{2}{12}<em> by multiplying the numerator and denominator by 2. And  </em>\frac{1}{4}<em> changes to </em>\frac{3}{12}<em> because you multiply the numerator and denominator by 3. </em>

<em></em>

<h3>3.) Add the numerators: </h3>
  • 2+3=5

<em>  - Since both fractions have the same denominator all you have to do is add the numerators together. </em>

<em />

______________________________

7 0
3 years ago
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