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Illusion [34]
3 years ago
13

Can a denominator be negative in rational number?

Mathematics
2 answers:
SpyIntel [72]3 years ago
7 0

Answer: Rational Numbers are the Numbers where if p/q, q is not equal to 0 and p is an integer. So according to this questionm denominators can’t have the negative rational numbers. If it has, we need to convert it to standard form, eg:- p/-q = -p/q

Annette [7]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

A \ rational  \ number \ is  \ a \ number\ of\ the\ form\ \frac{p}{q}, \\\\where\ p\ and\ q \ are\  integers\  and\  q \ not\  equal \  to\  zero.\\\\That\ means\ q\ can\ take\ any\ number\ positive\ or\ negative\ but\ zero.

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3 years ago
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What are the first and last terms of this geometric series
11Alexandr11 [23.1K]
ANSWER

E. 10 and 640


EXPLANATION


The given series is

\sum_{i=1}^45 \times 2^{2i-1}


To find the first term of the series we substitute i=1 to get,


a_1 = 5 \times  {2}^{2 \times 1 - 1}


a_1 = 5 \times  {2}^{ 1}  = 10



For the last term of the series, we substitute i=4 to obtain,

a_4 = 5 \times  {2}^{2 \times 4 - 1}


a_4 = 5 \times  {2}^{7}



This implies that,


a_4 = 5 \times  128 = 640


Therefore the correct answer is E
7 0
3 years ago
Simplify the following rational expression and express in expanded form.
VladimirAG [237]

Answer:

D m =  -\frac{3}{8}

Step-by-step explanation:

factor the expressions in the denominator and the numerator to simplify the expression:

=> \frac{2(-2m + 1)(2m - 1)}{2(2m - 1)(8m + 3)}

=> -\frac{2m + 1}{8m + 3}

to make a fraction undefined, the numerator should be 0, thus, we substitute the values of m from the options into the denominator to make the denominator equals to 0:

=> -\frac{2m + 1}{8(-\frac{3}{8} ) + 3} = -\frac{2m + 1}{-3 + 3} = -\frac{2m + 1}{0}

in this case, the values of m from option D make the denominator of the fraction equals 0.

6 0
3 years ago
How many hundreths need to reach 4 thents
grin007 [14]
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3 years ago
Adult tickets for the school musical are sold for $3.50 and student tickets are sold for $2.50 on a given night 425 tickets were
miskamm [114]

Answer:

3.5x + 2.50y = 1237.50

425 = x + y

Step-by-step explanation:

number of adult tickets: x

number of student tickets: y

3.5x + 2.50y = 1237.50

( value of adult ticket [3.50]* number of adult tickets [x]) + (value of student ticket [2.50] * number of student tickets [y]) = total value (1237.50)

425 = x + y

(number of adult tickets [x]) + (number of student tickets [y]) = total (425)

7 0
3 years ago
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