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Ksivusya [100]
3 years ago
9

Use the law of sines to find the value of w.

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0

Answer:

it is the answer b 4.0 cm

Step-by-step explanation:

Lunna [17]3 years ago
4 0

Option B: 4.0 cm is the value of w

Explanation:

It is given that \angle W= 39, \angle U=31, VW=3.3 and UV=w

Using the law of sines, we have,

\frac{sin U}{3.3} =\frac{sin W}{w}

Substituting the values, we have,

\frac{\sin 31}{3.3}=\frac{\sin 39}{w}

Cross multiplying, we get,

(sin31) w=3.3( \sin 39)

Simplifying, we have,

0.515w=2.077

Dividing both sides by 0.515, we have,

w=4.0

Thus, the value of w is 4.0 cm

Hence, Option B is the correct answer.

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A manager recorded how many hours each of 11 cashiers worked in a week. Which interval contains the median number of hours worke
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Answer:

Step-by-step explanation:

Hello!

In descriptive statistics, the median is a measurement of center position. It separates the sample in halves. (bottom 50% from upper 50%)

The manager took a sample of 11 cashiers and recorded the worked hours in a week

To identify the median you have to calculate it's position:

The position is calculated as

PosMe= (n+1)/2= (11+1)/2= 6 cashier

This means that the Median of hours worked is a week observed corresponds to the 6th cashier (after ordering the data from lowest to highest)

If you observe the histogram, the x-axis corresponds to worked hours and the y-axis shows the number of workers.

The workers were already arranged from least hours worked to most hours worked.

The first interval corresponds to 0-10 worked hours and two workers recorded these working times.

The second interval corresponds to 10-20 worked hours and three workers recorded these working times.

In the third interval of 20-30 hours, no workers recorded these working times.

The fourth interval corresponds to 30 - 40 worked hours and 5 workers recorded these working times.

The fifth interval corresponds to 40 - 50 worked hours and only one worker recorded these working hours.

The first five workers were recorded in the first two intervals and the sixth worker was recorded in the fourth interval. So the interval that contains the median number of hours worked is "30 - 40 hours"

I hope this helps!

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