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3 years ago

6

HELP PLZ DUE IN 10 MIN

1 answer:

slavikrds [6]3 years ago

5 0

Answer:

y = 4x+9 is the answer.

Step-by-step explanation:

Hope this helps:)

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Question 1 (1 point)

olga55 [171]

Answer:

1) $2y^{2}+4y-9$

2) $18x^{5}y^{4}z$

3) $6x^{5}-12x^{4}+9x^{3}$

4) 40

5) $x^{3}-7x^{2}+3x+36$

Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

$(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9$

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

$(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z$

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

$-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}$

4) $(4a+5)^{2}$ is a square of a sum, then, by definition you have:

$(a+b)^{2}=a^{2}+2ab+b^{2}$

Then:

$(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25$

The coefficient of the second term is the number in front of the variable <em>a.</em> Then, the answer is: 40

5) Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

$(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36$

6 0

3 years ago

1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than

zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 3, n = 8

$$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)$

$$=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)$

$$=\left(\frac{81}{11} , \frac{-43}{11}\right)$

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction $\frac{3}{8}$ .

Point divides segment in the ratio formula:

$$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)$

Here, $x_1=3, y_1=-5, x_2=19, y_2=-1$ and m = 7, n = 1

$$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)$

$$=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)$

$$=\left(\frac{136}{8} , \frac{-12}{8}\right)$

C(x, y) = (17, –1.5)

8 0

3 years ago

there are 148 juniors and 272 seniors attending prom this year. if there must be three chaperones per 60 students, how many chap

valkas [14]

21 chaperones are needed for 420 students.

Step-by-step explanation:

No. of juniors = 148

No. of seniors = 272

Total = 148+272 = 420 students

3 chaperones = 60 students

1 chaperone = $\frac{60}{3}=20\ students$

Ratio of chaperon to students = 1:20

Let,

x be the number of chaperons for 420 students.

Ration of chaperones to students = x:420

Using proportion

Ratio of chaperones to students :: Ratio of chaperons to students

$1:20::x:420$

Product of mean = Product of extreme

$20*x=420*1\\20x=420\\$

Dividing both sides by 20

$\frac{20x}{20}=\frac{420}{20}\\x=21$

21 chaperones are needed for 420 students.

Keywords: ratio, proportion

Learn more about ratios at:

#LearnwithBrainly

3 0

3 years ago

What is the solution to this system of equations?<br>5x + 2y = 29<br> x + 4y = 13

4vir4ik [10]

Answer:It would be 5,2 (Or C)

Step-by-step explanation:

6 0

3 years ago

What is the n?<br> -5 + n/4 = -1

marysya [2.9K]

Step-by-step explanation:

$- 5 + \frac{n}{4} = - 1$

$\frac{n}{4} = - 1 + 5$

$\frac{n}{4} = 4$

Cross multiply

therefore n = 16

Hope this helps

8 0

3 years ago

Read 2 more answers