A box contains 10 transistors, 3 of which are defective. If 3 are selected at random, find the probability that a. All are def
ective. b. None are defective.
2 answers:
3/10(2/9)(1/8)
3/10(3/9)(3/8)
A) 3/10 x 2/9 x 1/8= 1/120
b) 1-1/120=119/120
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