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3 years ago

Find the area of the shape below, giving your answer to 1 decimal place

Mathematics

2 answers:

Andre45 [30]3 years ago

7 0

Answer:the answer is 150

Step-by-step explanation:multiply 10 and 15 and you get 150

irga5000 [103]3 years ago

3 0

Answer:

$189.25 \: {cm}^{2}$

Step-by-step explanation:

Area of the shape = Area of rectangle + Area of semicircle.

For rectangle:

Length = 15 cm

Width = 10 cm

For semicircle:

Diameter = 10 cm

Radius = 10/2 = 5 cm

Area of the shape

$= lb + \frac{1}{2} \pi {r}^{2} \\ \\ = 15 \times 10 + \frac{1}{2} \times 3.14 \times {(5)}^{2} \\ \\ = 150 + \frac{1}{2} \times 3.14 \times 25 \\ \\ = 150 + 39.25 \\ \\ = 189.25 \: {cm}^{2}$

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OleMash [197]

Answer:

Concept: Series

Start by taking the first and second An and finding the difference
You can then prove your result by taking any ordinary An and subtracting it by An-1
Hence 45-39= 6
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2 years ago

Area of paralellogram with base 15cm and height12cm

azamat

Answer:

180 cm2

Area of a polyhedron:

15(=base)x12(=height)

=180cm2

btw parallelogram is a 2D pic how you can come out a ''base'' and ''height''? It should be called a polyhedron. Your question is weird.

If so, your ''area of parallelogram'' is 15cm2 since your question is hecking weird.

Btw it's 15cm2 not 15

Please check ur question b4 u ask

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2 years ago

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Change 84% to a fraction

Sauron [17]

21/25 first you would do 84/100 then you would simplify

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3 years ago

Ezra is training for a track race. He starts by sprinting 100 yards. He gradually increases his distance, adding 5 yards a day f

Sergeu [11.5K]

On the 21st day, he sprints 205 yards.

Is that what you meant for the problem

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3 years ago

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A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective

Inessa05 [86]

Answer:

(a) P(X $\leq$ 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

$P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....$

where, n = number of samples taken = 150

r = number of success

p = probability of success which in our question is % of bulbs that

are defective, i.e. 10%

Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.

So, Let X = No. of defective bulbs in a box

Mean of X, $\mu$ = $n \times p$ = $150 \times 0.10$ = 15

Standard deviation of X, $\sigma$ = $\sqrt{np(1-p)}$ = $\sqrt{150 \times 0.10 \times (1-0.10)}$ = 3.7

So, X ~ N( $\mu = 15, \sigma^{2} = 3.7^{2})$

Now, the z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X $\leq$ 20) = P(X < 20.5) ---- using continuity correction

P(X < 20.5) = P( $\frac{X-\mu}{\sigma}$ < $\frac{20.5-15}{3.7}$ ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = $n \times p$ = $150 \times 0.10$ = 15.

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3 years ago