Question

Which value is the 14th term of the sequence

Answer 1

This is a geometric sequence because it has a common ratio, denoted r, meaning that each term is a multiple of the previous term.

$a(n)=ar^{n-1}$, a=initial term, r=common ratio, n=term number

In this case a=$1 \over 81$ and r=3 (because each term is 3 time the previous term) so

$a(n)=(1/81)*3^{n-1}$

So the 14th term is:

a(14)=(1/81)$*3^{14}$=59049